Solve: $\frac{92+4 y}{12}+3 y=48$.

Academic Mathematics NCERT Class 10

Given: Expression: $\frac{92+4 y}{12}+3y=48$.

To do: To find $y$.

Solution:

Given Expression: $\frac{92+4 y}{12}+3y=48$.

$\Rightarrow \frac{92+4y+36y}{12}=48$

$\Rightarrow \frac{92+40y}{12}=48$

$\Rightarrow 92+40y=576$

$\Rightarrow 40y=576-92$

$\Rightarrow 40y=484$

$\Rightarrow y=\frac{484}{40}$

$\Rightarrow y=\frac{121}{10}$

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Updated on: 10-Oct-2022

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