Solve: $ \frac{0.2 y+5}{3.5 y-3}=\frac{2}{5} $

Given: 

$\frac{0.2 y+5}{3.5 y-3}=\frac{2}{5}$

To do: 

We have to find the value of $y$

Solution:

$\frac{0.2 y+5}{3.5 y-3}=\frac{2}{5}$

$\Rightarrow 5(0.2y+5)=2(3.5y-3)$         [by cross multiplication]

$\Rightarrow 1y+25=7y-6$   

$\Rightarrow 25+6=7y-1y$   

 $\Rightarrow 6y=31$   

 $\Rightarrow y=\frac {31}{6}$   

Thus the value of $y=\frac {31}{6}$.