Solve the following equations.
$ \frac{3 y+4}{2-6 y}=\frac{-2}{5} $.

Given:

\( \frac{3 y+4}{2-6 y}=\frac{-2}{5} \)

To do: 

We have to solve the given equation.

Solution:

$\frac{3 y+4}{2-6 y}=\frac{-2}{5}$

$\Rightarrow 5(3y+4)=(-2) \times(2-6y)$                [On cross multiplication]

$\Rightarrow 15y+20=-4+12y$

$\Rightarrow 15y-12y=-4-20$

$\Rightarrow 3y=-24$

$\Rightarrow y=\frac{-24}{3}$

$\Rightarrow y=-8$

The value of $y$ is $-8$.