In a circle of radius $ 21 \mathrm{~cm} $, an arc subtends an angle of $ 60^{\circ} $ at the centre. Find the length of the arc. (Use $ \pi=22 / 7 $ )
Given:
Radius of the circle $r=21 \mathrm{~cm}$.
Angle subtended by the arc $=60^{\circ}$
To do:
We have to find the length of the arc.
Solution:
Let the length of the arc be $l$.
We know that,
Length of arc $=2 \pi r(\frac{\theta}{360^{\circ}})$
Therefore,
Length of the arc $l=2 \times \frac{22}{7} \times 21 \times \frac{60^{\circ}}{360^{\circ}} \mathrm{cm}$
$=132 \times \frac{1}{6} \mathrm{cm}$
$=22 \mathrm{cm}$
The length of the arc is $22 \mathrm{~cm}$.
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