Find the angle subtended at the centre of a circle of radius ‘$a$’ by an arc of length ($\frac{a\pi}{4}$) cm.
Given:
Radius of the circle $=a$.
Length of the arc $=\frac{a\pi}{4}\ cm$
To do:
We have to find the angle subtended at the centre.
Solution:
Let $\theta$ be the angle subtended by the arc at the centre.
This implies,
$2 \pi r \times \frac{\theta}{360^{\circ}}=\frac{a \pi}{4}$
$\Rightarrow 2 \pi a \times \frac{\theta}{360^{\circ}}=\frac{a \pi}{4}$
$\Rightarrow \frac{\theta}{360^{\circ}}=\frac{a \pi}{4} \times \frac{1}{2 \pi a}$
$\Rightarrow \frac{\theta}{360^{\circ}}=\frac{1}{8}$
$\Rightarrow \theta=\frac{360^{\circ}}{8}$
$\Rightarrow \theta=45^{\circ}$
The angle subtended at the centre is $45^{\circ}$.
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