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In a circle of radius $ 6 \mathrm{~cm} $, a chord of length $ 10 \mathrm{~cm} $ makes an angle of $ 110^{\circ} $ at the centre of the circle. Find the circumference of the circle.
Given:
Radius of the circle $r=6 \mathrm{~cm}$.
Length of the arc $l=10 \mathrm{~cm}$.
Angle subtended at the centre $=110^{\circ}$.
To do:
We have to find the circumference of the circle.
Solution:
Let $OA$ and $OB$ are the radii of the circle and $AB$ the chord.
We know that,
Circumference of a circle of radius $r$ is $2 \pi r$.
Therefore,
Circumference of the circle $=2 \times 3.14 \times 6\ cm$
$=37.68\ cm$
The circumference of the circle is $37.68\ cm$.
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