In a circle of radius $ 6 \mathrm{~cm} $, a chord of length $ 10 \mathrm{~cm} $ makes an angle of $ 110^{\circ} $ at the centre of the circle. Find the circumference of the circle.

Given:

Radius of the circle $r=6 \mathrm{~cm}$.

Length of the arc $l=10 \mathrm{~cm}$.

Angle subtended at the centre $=110^{\circ}$.

To do:

We have to find the circumference of the circle.

Solution:

Let $OA$ and $OB$ are the radii of the circle and $AB$ the chord.

We know that,

Circumference of a circle of radius $r$ is $2 \pi r$.

Therefore,

Circumference of the circle $=2 \times 3.14 \times 6\ cm$

$=37.68\ cm$

The circumference of the circle is $37.68\ cm$.

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Updated on: 10-Oct-2022

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