Find the value of a if $4a^2-16a+16$.

The given equation is $4a^2 - 16a + 16$.

We have to find the value of a.

$4a^2 – 16a + 16 = 0$

$4(a^2 – 4a + 4) = 0$        (taking 4 as a common in the equation)

$a^2 – 4a + 4 = 0$             (dividing 0 by 4 gives 0)

$a^2 – 2a – 2a + 4 = 0$    (using prime factorization)

$a(a – 2) – 2(a – 2) = 0$

$(a – 2) (a – 2) = 0$

$(a – 2)^2 = 0$

$a-2=0$

$a = 2$

The value of a is 2.

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Updated on: 10-Oct-2022

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