Find the value of $\frac{4a^2-9b^2}{2a+3b}$.

To do: To find the value of $\frac{4a^2-9b^2}{2a+3b}$.

Solution: 

$\frac{4a^2-9b^2}{2a+3b}$

$=\frac{( 2a)^2-( 3b)^2}{2a+3b}$

$=\frac{( 2a-3b)( 2a+3b)}{2a+3b}$

$=2a-3b$

Tutorialspoint

Updated on: 10-Oct-2022

37 Views

Kickstart Your Career

Get certified by completing the course

Get Started