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The perimeter$\ ( in\ cm)$ of a square circumscribing a circle of radius a cm, is:
$( A) \ 8a$
$( B) \ 4a$
$( C) \ 2a$
$( D) \ 16a$
Given: A circle with radius a cm and a square circumscribing the circle.
To do: To find out the perimeter of the square in cm.
Solution:
Here we draw a figure, a circle of radius a with centre O. and a square ABCD circumscribing the circle.
Let us say that the circumscribing square touches the circle on P, Q, R and S.
Then$\ OP=OQ=OR=OS=a\ cm$
$\therefore \ OP\bot AD,\ OQ\bot AB,\ OS\bot BC\ $and $OR\bot CD.$
And $PS=OP+OS=a+a=2a$ and here $PS=AB=2a$
$\therefore$ Perimeter of a square$A=4\times 2a\ =8a\ cm$
Option $( A)$ is correct.
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