Find the product of the following:$7ab^2, (−4a^4b^3)$.

Given: $7ab^2$ and $(−4a^4b^3)$

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To find: We have to find the product of $7ab^2$ and $(−4a^4b^3)$

Solution:

Exponents problems can be solved easily using the laws of exponents.

• $p^m \times p^n = p^{m+n}$

$7ab^2 \times (−4a4b^3) = -28 [a\times a^4][b^2\times b^2]$

Thus, the product of the expression is $-28a^5b^5$

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Updated on: 10-Oct-2022

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