Find the perimeter of the square whose area is $2500 m^{2}$.

Given :

The area of the square is $2500 m^2$.

To do :

We have to find the perimeter of the square.

Solution :

The area of the square with the length of the side 'a' is $a^2$.

 So, $a^2 = 2500 m^2$

$a = \sqrt{2500}$

$a=\sqrt{50 \times 50}$

$a = 50 m$.

The perimeter of the square with the length of the side 'a' is $4a$.

Perimeter $= 4 \times 50 = 200 m$.

The perimeter of the square is 200 m.

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Updated on: 10-Oct-2022

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