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# Find the area of a square park whose perimeter is $320\ m$.

Given :

Perimeter of a square $= 320 m$.

To find :

We have to find the area of the square.

Solution :

Perimeter of a square of side \'s\' is 4s.

$ 4a = 320 m$ (Where a is the side length of the square)

$a = \frac{320}{4} m$

$a = 80 m$

Now,

$$Area of a square = a^2$$

Area of a square $= (80)^2 m^2$

Area of a square $= 6400 m^2$.

Therefore, the area of the square is $6400 m^2$.

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