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Find the area of a square park whose perimeter is $320\ m$.
Given :
Perimeter of a square $= 320 m$.
To find :
We have to find the area of the square.
Solution :
Perimeter of a square of side 's' is 4s.
$ 4a = 320 m$ (Where a is the side length of the square)
$a = \frac{320}{4} m$
$a = 80 m$
Now,
$$Area of a square = a^2$$
Area of a square $= (80)^2 m^2$
Area of a square $= 6400 m^2$.
Therefore, the area of the square is $6400 m^2$.
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