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The area of a rectangular field whose length is twice its breadth is 2450 square meter. Find the perimeter of the field.
Given :
Area of the Rectangular field = 2450 sq m.
Length of the rectangular field is twice its breadth.
To find :
We have to find the Perimeter of the Rectangular field.
Solution :
It is given that, length of the rectangular field is twice its breadth.
$Length = 2\times Breadth$ ........................(I)
We know that, Area of rectangle $=length \times breadth$
$2450 = length\times breadth$.......................(ii)
Substitute (i) in (ii)
$2450 = 2\times breadth\times breadth $
$2450 = 2 breadth^{2}$
$\frac{2450}{2} = breadth^{2}$
$1225 = breadth^{2}$
$\sqrt{1225} = breadth$
$35 = breadth$
The breadth of Rectangular field = 35 m.
Substitute breadth value in (I),
$Length = 2\times Breadth$
$ Length = 2\times 35 $
$Length = 70$
Length of Rectangular field = 70 m.
Perimeter of rectangle $= 2(Length + breadth)$
$= 2(70 + 35)$
$ = 2(105) = 210$
Perimeter = 210 m
The perimeter of the rectangular field is 210 m.
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