Find the mean of each of the following frequency distribution:
Class interval:0-88-1616-2424-3232-40
Frequency:591088.


To do:

We have to find the mean of the given frequency distribution.

Solution:

Let the assumed mean be $A=20$


 We know that,

Mean $=A+\frac{\sum{f_id_i}}{\sum{f_i}}$    

Therefore,  

Mean $=20+\frac{40}{40}$

$=20+1$

$=21$

The mean of the given frequency distribution is $21$.

Updated on: 10-Oct-2022

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