Find the following product.
$\frac{1}{2} x y \times \frac{2}{3} x^{2} y z^{2}$
Given:
$\frac{1}{2} x y \times \frac{2}{3} x^{2} y z^{2}$
To do:
We have to find the given product.
Solution:
$\frac{1}{2} x y \times \frac{2}{3} x^{2} y z^{2}=[\frac{1}{2}\times\frac{2}{3}]\times(xy \times x^2yz^2)$
$=\frac{1}{3}\times x^{1+2}\times y^{1+1}\times z^2$
$=\frac{1}{3}x^3y^2z^2$
- Related Articles
- Find the following product.\( \left(\frac{-7}{5} x y^{2} z\right) \times\left(\frac{13}{3} x^{2} y z^{2}\right) \)
- Find the following product.\( (0.5 x) \times\left(\frac{1}{3} x y^{2} z^{4}\right) \times\left(-24 x^{2} y z\right) \)
- Find the product $-\frac{2}{5} x^{2} y^{2}(\frac{3 x}{2}-y^{2})$.
- Find the product of $(-3 x y z)(\frac{4}{9} x^{2} z)(-\frac{27}{2} x y^{2} z)$ and verify the result for ; $x=2, y=3$ and $z=-1$
- Verify that \( x^{3}+y^{3}+z^{3}-3 x y z=\frac{1}{2}(x+y+z)\left[(x-y)^{2}+(y-z)^{2}+(z-x)^{2}\right] \)
- Verify: $x\times(y\times z)=(x\times y)\times z$, where $x=\frac{1}{2},\ y=\frac{1}{3}$ and $z=\frac{1}{4}$.
- Find the following products:\( \frac{-8}{27} x y z\left(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3}\right) \)
- Simplify each of the following expressions:\( (x+y+z)^{2}+\left(x+\frac{y}{2}+\frac{z}{3}\right)^{2}-\left(\frac{x}{2}+\frac{y}{3}+\frac{z}{4}\right)^{2} \)
- Find the following products:\( \frac{-4}{27} x y z\left[\frac{9}{2} x^{2} y z-\frac{3}{4} x y z^{2}\right] \)
- Find the following product.\( (-7 x y) \times\left(\frac{1}{4} x^{2} y z\right) \)
- If \( 2^{x}=3^{y}=12^{z} \), show that \( \frac{1}{z}=\frac{1}{y}+\frac{2}{x} \).
- \Find $(x +y) \div (x - y)$. if,(i) \( x=\frac{2}{3}, y=\frac{3}{2} \)(ii) \( x=\frac{2}{5}, y=\frac{1}{2} \)(iii) \( x=\frac{5}{4}, y=\frac{-1}{3} \)(iv) \( x=\frac{2}{7}, y=\frac{4}{3} \)(v) \( x=\frac{1}{4}, y=\frac{3}{2} \)
- If $\frac{x+1}{y} = \frac{1}{2}, \frac{x}{y-2} = \frac{1}{2}$, find x and y.
- Simplify: \( \frac{11}{2} x^{2} y-\frac{9}{4} x y^{2}+\frac{1}{4} x y-\frac{1}{14} y^{2} x+\frac{1}{15} y x^{2}+\frac{1}{2} x y \).
- Verify associativity of addition of rational numbers i.e., $(x + y) + z = x + (y + z)$, when:(i) \( x=\frac{1}{2}, y=\frac{2}{3}, z=-\frac{1}{5} \)(ii) \( x=\frac{-2}{5}, y=\frac{4}{3}, z=\frac{-7}{10} \)(iii) \( x=\frac{-7}{11}, y=\frac{2}{-5}, z=\frac{-3}{22} \)(iv) \( x=-2, y=\frac{3}{5}, z=\frac{-4}{3} \)
Kickstart Your Career
Get certified by completing the course
Get Started