Find the following products:
$ \frac{-8}{27} x y z\left(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3}\right) $
Given:
\( \frac{-8}{27} x y z\left(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3}\right) \)
To do:
We have to find the given product.
Solution:
$\frac{-8}{27} x y z(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3})=\frac{-8}{27} x y z \times \frac{3}{2} x y z^{2}+(\frac{-8}{27} x y z) \times(\frac{-9}{4} x y^{2} z^{3})$
$=\frac{-4}{9} x^{1+1} y^{1+1} z^{1+2}+\frac{2}{3} x^{1+1} y^{1+2} z^{1+3}$
$=\frac{-4}{9} x^{2} y^{2} z^{3}+\frac{2}{3} x^{2} y^{3} z^{4}$
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