Find the product $-\frac{2}{5} x^{2} y^{2}(\frac{3 x}{2}-y^{2})$.
Given:
$-\frac{2}{5} x^{2} y^{2}(\frac{3 x}{2}-y^{2})$.
To do:
We have to find the product.Solution: $-\frac{2}{5} x^{2} y^{2}(\frac{3 x}{2}-y^{2})=-\frac{2}{5} x^{2} y^{2}(\frac{3 x}{2})-\frac{2}{5} x^{2} y^{2}(-y^{2})$
$=-(\frac{2\times3}{5\times2})x^{(2+1)} y^{2}+\frac{2}{5} x^{2} y^{(2+2)}$
$=-\frac{3}{5} x^{3} y^{2}+\frac{2}{5} x^{2} y^{4}$
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\Find $(x +y) \div (x - y)$. if,(i) \( x=\frac{2}{3}, y=\frac{3}{2} \)(ii) \( x=\frac{2}{5}, y=\frac{1}{2} \)(iii) \( x=\frac{5}{4}, y=\frac{-1}{3} \)(iv) \( x=\frac{2}{7}, y=\frac{4}{3} \)(v) \( x=\frac{1}{4}, y=\frac{3}{2} \)
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If $\frac{x+1}{y} = \frac{1}{2}, \frac{x}{y-2} = \frac{1}{2}$, find x and y.
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If $\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}=x,\ \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}=y$, find the value $x^{2}+y^{2}+x y$.
Find the following product.\( \left(\frac{-7}{5} x y^{2} z\right) \times\left(\frac{13}{3} x^{2} y z^{2}\right) \)
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