Divide the sum of $ \frac{65}{12} $ and $ \frac{8}{3} $ by their difference.

Given: 

$\frac{65}{12}$ and $\frac{8}{3}$

To do: 

Here we have to divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.

Solution:

Sum of $\frac{65}{12}$ and $\frac{8}{3}$:

$\frac{65}{12} \ +\ \frac{8}{3}$

$=\frac{65 + 8(4)}{12}$     (LCM of 12 and 3 is 12)

$=\frac{65 + 32}{12}$

$= \frac{97}{12}$

Difference of $\frac{65}{12}$ and $\frac{8}{3}$:

$\frac{65}{12} \ -\ \frac{8}{3}$

$=\ \frac{65 \ -\ 8( 4)}{12}$

$=\ \frac{65\ -\ 32}{12}$

$=\ \mathbf{\frac{33}{12}}$

Now, dividing the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference;

$=\ \frac{\frac{97}{12}}{\frac{33}{12}}$

$=\ \frac{97}{12} \ \times \ \frac{12}{33}$

$= \frac{97}{33}$

$=\ \mathbf{\frac{97}{33}}$

So, answer is $\frac{97}{33}$. 

Tutorialspoint

Updated on: 10-Oct-2022

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