Divide:

The sum of $ \frac{5}{21} $ and $ \frac{4}{7} $ by their difference.

Given: $\frac{5}{21}$ and $\frac{4}{7}$

To do: Here we have to divide the sum of $\frac{5}{21}$ and $\frac{4}{7}$ by their difference.

Solution:

Sum of $\frac{5}{21}$ and $\frac{4}{7}$:

$\frac{5}{21} \ +\ \frac{4}{7}$

$=\ \frac{1( 5) \ +\ 3( 4)}{21}$

$=\ \frac{5\ +\ 12}{21}$

$=\ \mathbf{\frac{17}{21}}$

Difference of $\frac{5}{21}$ and $\frac{4}{7}$:

$\frac{4}{7} \ -\ \frac{5}{21}$

$=\ \frac{3( 4) \ -\ 1( 5)}{21}$

$=\ \frac{12\ -\ 5}{21}$

$=\ \mathbf{\frac{7}{21}}$

Now, dividing the sum of $\frac{5}{21}$ and $\frac{4}{7}$ by their difference;

$=\ \frac{\frac{17}{21}}{\frac{7}{21}}$

$=\ \frac{17}{21} \ \times \ \frac{21}{7}$

$=\ \frac{17}{1} \ \times \ \frac{1}{7}$

$=\ \mathbf{\frac{17}{7}}$

So, answer is $\frac{17}{7}$.

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Updated on: 10-Oct-2022

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