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What is the sum of $ \frac{9}{8} $ and $ -\frac{11}{8} $?
Given:
Given fractions are \( \frac{9}{8} \) and \( -\frac{11}{8} \).
To do:
We have to find the sum of \( \frac{9}{8} \) and \( -\frac{11}{8} \).
Solution:
$\frac{9}{8}+\frac{-11}{8}=\frac{9+(-11)}{8}$
$=\frac{9-11}{8}$
$=\frac{-2}{8}$
$=\frac{-1}{4}$
The sum of \( \frac{9}{8} \) and \( -\frac{11}{8} \) is $\frac{-1}{4}$.
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