A piggy bank contains hundred 50 paise coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be a 50 paise coin.
Given:

A piggy bank contains hundred 50 paise coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins.

It is equally likely that one of the coins will fall out when the bank is turned upside down.

To do:

We have to find the probability that the coin which fell will be a 50 paise coin.

Solution:

Number of 50 paise coins $=100$

Number of Rs. 1 coins $=50$

Number of Rs. 2 coins $=20$

Number of Rs. 5 coins $=10$

This implies,

Total number of coins $=100+50+20+10=180$

The total number of possible outcomes $n=180$.

Total number of favourable outcomes(50 paise coin falling) $=100$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability that the coin which fell will be a 50 paise coin.

$=\frac{100}{180}$

$=\frac{5}{9}$

The probability that the coin which fell will be a 50 paise coin is $\frac{5}{9}$.

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