A piggy bank contains hundred 50 paise coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be a 50 paise coin.
Given:
A piggy bank contains hundred 50 paise coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins.
It is equally likely that one of the coins will fall out when the bank is turned upside down.
To do:
We have to find the probability that the coin which fell will be a 50 paise coin.
Solution:
Number of 50 paise coins $=100$
Number of Rs. 1 coins $=50$
Number of Rs. 2 coins $=20$
Number of Rs. 5 coins $=10$
This implies,
Total number of coins $=100+50+20+10=180$
The total number of possible outcomes $n=180$.
Total number of favourable outcomes(50 paise coin falling) $=100$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the coin which fell will be a 50 paise coin.
$=\frac{100}{180}$
$=\frac{5}{9}$
The probability that the coin which fell will be a 50 paise coin is $\frac{5}{9}$.
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