Three coins are tossed. Find the probability of getting atmost one head.

Given: Three coins are tossed.

To do: To find the probability of getting atmost one head.

When three coins are tossed, outcomes are :-HHH, HHT, HTH, THH, TTT, TTH, THT, HTT.

\therefore Total possible outcomes$=8$

nomber of events of getting atmost head $=3$

The probability of getting atmost one head $=\frac{Total\ no.\ favorable\ outcomes}{Total\ no.\ possible\ outcomes}=\frac{3}{8}$