A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.
Given :
A father is three times as old as his son. After twelve years, his age will be twice as that of his son then.
To find :
We have to find their present ages.
Solution :
Let the present age of the son be $x$.
This implies,
The age of the father $= 3x$
Age of the son after 12 years $= x+12$
Age of the father after 12 years $= 3x+12$.
After twelve years, the father's age will be twice as that of his son.
Therefore,
$3x+12 = 2(x+12)$
$3x+12 = 2x+24$
$3x-2x = 24-12$
$x = 12$
$\Rightarrow 3x=3(12)=36$ years
The present age of the son is $12$ years and the present age of the father is $36$ years.
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