# A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.

Given :

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then.

To find :

We have to find their present ages.

Solution :

Let the present age of the son be $x$.

This implies,

The age of the father $= 3x$

Age of the son after 12 years $= x+12$

Age of the father after 12 years $= 3x+12$.

After twelve years, the father's age will be twice as that of his son.

Therefore,

$3x+12 = 2(x+12)$

$3x+12 = 2x+24$

$3x-2x = 24-12$

$x = 12$

$\Rightarrow 3x=3(12)=36$ years

The present age of the son is $12$ years and the present age of the father is $36$ years.

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