A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.



Given: A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages.

To do: To find the present age of the father. 

Solution:
Let the sum of two son's present age$=x$ years

$\therefore$ Father's age$=3x$                 .................$( 1)$

After 5 years,

Sum of the son's age $=( x+10)$years

Father's age $=3x+5$

According to the given question,

$3x+5=2( x+10)$

$\Rightarrow 3x+5=2x+20$

$\Rightarrow 3x-2x=20-5$

$\Rightarrow x=15$ years

Thus father's age will be $3x=3×15=45$ years.

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Updated on: 10-Oct-2022

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