A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.
Given: A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages.
To do: To find the present age of the father.
Solution:
Let the sum of two son's present age$=x$ years
$\therefore$ Father's age$=3x$ .................$( 1)$
After 5 years,
Sum of the son's age $=( x+10)$years
Father's age $=3x+5$
According to the given question,
$3x+5=2( x+10)$
$\Rightarrow 3x+5=2x+20$
$\Rightarrow 3x-2x=20-5$
$\Rightarrow x=15$ years
Thus father's age will be $3x=3×15=45$ years.
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