# Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

**Given:**

A father's age is three times the sum of the ages of his two children. After 5 years his age will be twice the sum of the ages of two children.

**To do: **

To find the present age of the father.

Solution:

Let the sum of two sons' present ages be $x$ years.

This implies,

Father's age$=3x$.....(i)

After 5 years,

The sum of the sons' ages $=( x+10)$

Father's age $=3x+5$

According to the given question,

$3x+5=2(x+10)$

$\Rightarrow 3x+5=2x+20$

$\Rightarrow 3x-2x=20-5$

$\Rightarrow x=15$ years

Therefore,

Father's age $3x=3\times15=45$ years.

**The age of the father is 45 years.**

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