- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Somu's age is half the age of his sister. If after twelve years his sister will become 26 years old, find the present ages of Somu and his sister.
Given :
Somu's age is half the age of his sister.
After twelve years his sister will become 26 years old.
To find :
We have to find the present ages of Somu and his sister.
Solution :
Let the present age of the Somu be $x$.
This implies,
The present age of his sister $= 2x$
Age of Somu after 12 years $= x+12$
Age of his sister after 12 years $= 2x+12$.
Therefore,
$2x+12 =26$
$2x = 26-12$
$2x = 14$
$x = \frac{14}{2}=7$
$\Rightarrow 2x=2(7)=14$ years
The present age of Somu is $7$ years and the present age of his sister is $14$ years.
Advertisements