Sunil's father is 3 times as old as Sunil. After 10 years his age will be twice the age of his son. Find their present ages.


Given :

Age of Sunil's father is 3 times the age of Sunil.

After 10 years his age will be twice the age of Sunil.


To find :

We have to find their present ages.


Solution : 

Let the present age of Sunil be $x$.

The age of Sunil's father = $3x$

Age of Sunil after 10 years $= x+10$

Age of Sunil's father after 10 years $= 3x+10$

Therefore,

$3x+10 = 2(x+10)$

$3x+10 = 2x+20$

$3x-2x = 20-10$

$x = 10$


The present age of Sunil is 10 years.

The present age of Sunil's father is 3(10) = 30 years.

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Updated on: 10-Oct-2022

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