A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.
Given :
A man is 4 times as old as his son.
After 16 years, he will be only twice as old as his son.
To do :
We have to find their present ages.
Solution :
Let the age of the son be x.
This implies, the age of the man $= 4x$.
After 16 years,
Age of son $= x+16$
Age of the man $= 4x+16$
Therefore,
$4x+16=2(x+16)$
$4x+16=2x+32$
$4x-2x=32-16$
$2x=16$
$x=\frac{16}{2}$
$x=8$
$4 x = 4(8)=32$
Their present ages are 8 years and 32 years.
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