Groovy - List reverseEach(Closure closure) method

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Description

Groovy List reverseEach(Closure closure) method iterates over each element in reverse order while passing each element to the passed closure.

Syntax

public List reverseEach(Closure closure)

Parameters

closure − A closure getting each element of the list.

Return Value

The original list.

Example - Printing a List of Integers in reverse order

Following is an example of the usage of this method −

main.groovy

def lst = [11, 12, 13, 14]

def revlst = lst.reverseEach {println it}

Output

When we run the above program, we will get the following result −

14
13
12
11

Example - Printing a List of Strings in reverse order

Following is an example of the usage of this method −

main.groovy

def lst = ["Apple", "Peach", "Orange", "Mango"]

def revlst = lst.reverseEach {println it}

Output

When we run the above program, we will get the following result −

Mango
Orange
Peach
Apple

Example - Printing a List of Objects in reverse order

Following is an example of the usage of this method −

main.groovy

def lst = [new Student(1, "Julie"),new Student(2, "Robert"),new Student(3, "Adam")]

def revlst = lst.reverseEach {println it}

class Student {
   int rollNo;
   String name;

   Student(int rollNo, String name){
      this.rollNo = rollNo;
      this.name = name;
   }

   @Override
   public boolean equals(Object obj) {
      Student s = (Student)obj;
      return this.rollNo == s.rollNo && this.name.equalsIgnoreCase(s.name);
   }
   
   @Override
   public String toString() {
      return "[ " + this.rollNo + ", " + this.name + " ]";
   }
}

Output

When we run the above program, we will get the following result −

[ 3, Adam ]
[ 2, Robert ]
[ 1, Julie ]