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Fill in the blanks:
(a) $ 369 \div \square=369 $
(b) $ (-75) \div \square=-1 $
(c) $ (-206) \div \square=1 $
(d) $ -87 \div \square=87 $
(e) $ \square \div -1=-87 $
(f) $ \square \div 48=-1 $
(g) $ 20 \div \square=-2 $
(h) $ \square \div(4)=-3 $
To do:
We have to fill in the blanks.
Solution:
We know that,
$a \div b=a\times \frac{1}{b}$
Therefore,
(a) Let the number in the blank be $x$.
This implies,
$369 \div x= 369$
$369 \times \frac{1}{x}=369$
$x=\frac{369}{369}$
$x=1$
(b) Let the number in the blank be $x$.
This implies,
$-75 \div x= -1$
$-75 \times \frac{1}{x}=-1$
$x=\frac{-75}{-1}$
$x=75$
(c) Let the number in the blank be $x$.
This implies,
$-206 \div x= 1$
$-206 \times \frac{1}{x}=1$
$x=\frac{-206}{1}$
$x=-206$
(d) Let the number in the blank be $x$.
This implies,
$-87 \div x= 87$
$-87 \times \frac{1}{x}=87$
$x=\frac{-87}{87}$
$x=-1$
(e) Let the number in the blank be $x$.
This implies,
$x \div -1= -87$
$x \times \frac{1}{-1}=-87$
$x=-87\times(-1)$
$x=87$
(f) Let the number in the blank be $x$.
This implies,
$x \div 48= -1$
$x \times \frac{1}{48}=-1$
$x=-1\times48$
$x=-48$
(g) Let the number in the blank be $x$.
This implies,
$20 \div x= -2$
$20 \times \frac{1}{x}=-2$
$x=\frac{20}{-2}$
$x=-10$
(h) Let the number in the blank be $x$.
This implies,
$x \div 4= -3$
$x \times \frac{1}{4}=-3$
$x=-3\times4$
$x=-12$