# Fill in the blanks:(a) $369 \div \square=369$(b) $(-75) \div \square=-1$(c) $(-206) \div \square=1$(d) $-87 \div \square=87$(e) $\square \div -1=-87$(f) $\square \div 48=-1$(g) $20 \div \square=-2$(h) $\square \div(4)=-3$

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To do:

We have to fill in the blanks.

Solution:

We know that,

$a \div b=a\times \frac{1}{b}$

Therefore,

(a) Let the number in the blank be $x$.

This implies,

$369 \div x= 369$

$369 \times \frac{1}{x}=369$

$x=\frac{369}{369}$

$x=1$

(b) Let the number in the blank be $x$.

This implies,

$-75 \div x= -1$

$-75 \times \frac{1}{x}=-1$

$x=\frac{-75}{-1}$

$x=75$

(c) Let the number in the blank be $x$.

This implies,

$-206 \div x= 1$

$-206 \times \frac{1}{x}=1$

$x=\frac{-206}{1}$

$x=-206$

(d) Let the number in the blank be $x$.

This implies,

$-87 \div x= 87$

$-87 \times \frac{1}{x}=87$

$x=\frac{-87}{87}$

$x=-1$

(e) Let the number in the blank be $x$.

This implies,

$x \div -1= -87$

$x \times \frac{1}{-1}=-87$

$x=-87\times(-1)$

$x=87$

(f) Let the number in the blank be $x$.

This implies,

$x \div 48= -1$

$x \times \frac{1}{48}=-1$

$x=-1\times48$

$x=-48$

(g) Let the number in the blank be $x$.

This implies,

$20 \div x= -2$

$20 \times \frac{1}{x}=-2$

$x=\frac{20}{-2}$

$x=-10$

(h) Let the number in the blank be $x$.

This implies,

$x \div 4= -3$

$x \times \frac{1}{4}=-3$

$x=-3\times4$

$x=-12$

Updated on 10-Oct-2022 13:31:02