# Evaluate each of the following:(a) $(-30) \div 10$(b),/b> $50 \div (-5)$(c),/b> $(-36) \div (-9)$(d),/b> $(- 49) \div (49)$(e),/b> $13 \div [(-2) + 1]$(f),/b> $0 \div (-12)$(g),/b> $(-31) \div [(-30) + (-1)]$(h),/b> $[(-36)\div 12] \div 3$(i),/b> $[(- 6) + 5)] \div [(-2) + 1]$

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To do:

We have to evaluate the given expressions.

Solution:

We know that,

$a \div b=a \times \frac{1}{b}$

Therefore,

(a) $(-30) \div 10$

$=(-30)\times \frac{1}{10}$

$=-3$

(b) $50 \div (-5)$

$=50\times (-\frac{1}{5})$

$=-\frac{50}{5}$

$=-10$

(c) $(-36) \div (-9)$

$=(-36)\times\frac{1}{-9}$

$=\frac{-36}{-9}$

$=4$

(d) $(- 49) \div (49)$

$=(-49)\times \frac{1}{49}$

$=-1$

(e) $13 \div [(-2) + 1]$

$=13\div [-2+1]$

$=13\div [-1]$

$=13\times \frac{1}{-1}$

$=-13$

(f) $0 \div (-12)$

$=0\times\frac{1}{-12}$

$=\frac{0}{-12}$

$=0$

(g) $(-31) \div [(-30) + (-1)]$

$=-31\div [-30-1]$

$=-31\div [-31]$

$=-31\times (-\frac{1}{31})$

$=\frac{-31}{-31}$

$=1$

(h) $[(-36) \div 12] \div 3$

$=[-36\div 12]\div 3$

$=[-36\times\frac{1}{12}]\div 3$

$=[\frac{-36}{12}]\div 3$

$=[-3]\div 3$

$=(-3)\times\frac{1}{3}$

$=-\frac{3}{3}$

$=-1$

(i) $[(- 6) + 5)] \div [(-2) + 1]$

$=[-6+5]\div[-2+1]$

$=[-1]\div [-1]$

$=-1\times \frac{1}{-1}$

$=\frac{-1}{-1}$

$=1$

Updated on 10-Oct-2022 13:31:02