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Evaluate each of the following:
(a) $(-30) \div 10$
(b),/b> $50 \div (-5)$
(c),/b> $(-36) \div (-9)$
(d),/b> $(- 49) \div (49)$
(e),/b> $13 \div [(-2) + 1]$
(f),/b> $0 \div (-12)$
(g),/b> $(-31) \div [(-30) + (-1)]$
(h),/b> $[(-36)\div 12] \div 3$
(i),/b> $[(- 6) + 5)] \div [(-2) + 1]$
To do:
We have to evaluate the given expressions.
Solution:
We know that,
$a \div b=a \times \frac{1}{b}$
Therefore,
(a) $(-30) \div 10$
$=(-30)\times \frac{1}{10}$
$=-3$
(b) $50 \div (-5)$
$=50\times (-\frac{1}{5})$
$=-\frac{50}{5}$
$=-10$
(c) $(-36) \div (-9)$
$=(-36)\times\frac{1}{-9}$
$=\frac{-36}{-9}$
$=4$
(d) $(- 49) \div (49)$
$=(-49)\times \frac{1}{49}$
$=-1$
(e) $13 \div [(-2) + 1]$
$=13\div [-2+1]$
$=13\div [-1]$
$=13\times \frac{1}{-1}$
$=-13$
(f) $0 \div (-12)$
$=0\times\frac{1}{-12}$
$=\frac{0}{-12}$
$=0$
(g) $(-31) \div [(-30) + (-1)]$
$=-31\div [-30-1]$
$=-31\div [-31]$
$=-31\times (-\frac{1}{31})$
$=\frac{-31}{-31}$
$=1$
(h) $[(-36) \div 12] \div 3$
$=[-36\div 12]\div 3$
$=[-36\times\frac{1}{12}]\div 3$
$=[\frac{-36}{12}]\div 3$
$=[-3]\div 3$
$=(-3)\times\frac{1}{3}$
$=-\frac{3}{3}$
$=-1$
(i) $[(- 6) + 5)] \div [(-2) + 1]$
$=[-6+5]\div[-2+1]$
$=[-1]\div [-1]$
$=-1\times \frac{1}{-1}$
$=\frac{-1}{-1}$
$=1$
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