Solve the following:

1. $16 \div 8+10-40 \times 0$

2. $(-30) \times(-1)+100 \div 10$


Given:


\( 1.16 \div 8+10-40 \times 0 \)

\( 2 \cdot(-30) \times(-1)+100 \div 10 \)


To do:


We have to simplify the given expressions.

Solution:


We have to follow Bodmas method in these type of problems.

1.

$ \begin{array}{l}
16\div 8+10-40\times 0=\frac{16}{2} +10-0\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =8+10\\
\ \\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =18
\end{array}$

2.

$ \begin{array}{l}
( -30) \times ( -1) +100\div 10=30+\frac{100}{10} \ \ \ \ \ \ \ \ \ \ \ \ [( -) \times ( -) =( +)]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30+10\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =40
\end{array}$

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Updated on: 10-Oct-2022

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