Find:
$(i).\ 0.4 \div 2$
$(ii).\ 0.35 \div 5$
$(iii).\ 2.48 \div 4$
$(iv).\ 65.4 \div 6$
$(v).\ 651.2 \div 4$
$(vi).\ 14.49 \div 7$
$(vii).\ 3.96 \div 4$
$(viii).\ 0.80 \div 5$

AcademicMathematicsNCERTClass 7

To do:

We have to find

(i) $0.4 \div 2$

(ii) $0.35 \div 5$

(iii) $2.48 \div 4$

(iv) $65.4 \div 6$

(v) $651.2 \div 4$

(vi) $14.49 \div 7$

(vii) $3.96 \div 4$

(viii) $0.80 \div 5$

Solution:

We know that,

On dividing a decimal by $10^n$, the decimal point shifts to the left by $n$ places.

$\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$

Therefore,

(i) $0.4 \div 2=\frac{4}{10}\div2$

$=\frac{4}{10}\times\frac{1}{2}$

$=\frac{4\times1}{10\times2}$

$=\frac{2}{10}$

$=0.2$

(ii) $0.35 \div 5=\frac{35}{100}\div5$

$=\frac{35}{100}\times\frac{1}{5}$

$=\frac{35\times1}{100\times5}$

$=\frac{7}{100}$

$=0.07$  

(iii) $2.48 \div 4=\frac{248}{100}\div4$

$=\frac{248}{100}\times\frac{1}{4}$

$=\frac{62}{100}$

$=0.62$

(iv) $65.4 \div 6=\frac{654}{10}\div6$

$=\frac{654}{10}\times\frac{1}{6}$

$=\frac{109}{10}$

$=10.9$

(v) $651.2 \div 4=\frac{6512}{10}\times\frac{1}{4}$

$=\frac{6512\times1}{10\times4}$

$=\frac{1628}{10}$

$=162.8$

(vi) $14.49 \div 7=\frac{1449}{100}\times\frac{1}{7}$

$=\frac{1449\times1}{100\times7}$

$=\frac{207}{100}$

$=2.07$

(vii) $3.96 \div 4=\frac{396}{100}\times\frac{1}{4}$

$=\frac{396\times1}{100\times4}$

$=\frac{99}{100}$

$=0.99$

(viii) $0.80 \div 5=\frac{80}{100}\times\frac{1}{5}$

$=\frac{80\times1}{100\times5}$

$=\frac{16}{100}$

$=0.16$

raja
Updated on 10-Oct-2022 13:32:37

Advertisements