Find:
(i) $12\div\frac{3}{4}$
(ii) $14\div\frac{5}{6}$
(iii) $8\div\frac{7}{3}$
(iv) $4\div\frac{8}{3}$
(v) $3\div2\frac{1}{3}$
(vi) $5\div3\frac{4}{7}$

AcademicMathematicsNCERTClass 7

To do:

We have to find

(i) $12\div\frac{3}{4}$

(ii) $14\div\frac{5}{6}$

(iii) $8\div\frac{7}{3}$

(iv) $4\div\frac{8}{3}$

(v) $3\div2\frac{1}{3}$

(vi) $5\div3\frac{4}{7}$

Solution:

We know that,

$\frac{a}{b} \div \frac{c}{d}=\frac{a}{b} \times \frac{d}{c}$

Therefore,

(i) $12\div\frac{3}{4}=12\times\frac{1}{\frac{3}{4}}$

$=12\times\frac{4}{3}$

$=\frac{12\times4}{3}$

$=\frac{48}{3}$

$=16$

(ii) $14\div\frac{5}{6}=14\times\frac{1}{\frac{5}{6}}$

$=14\times\frac{6}{5}$

$=\frac{14\times6}{5}$

$=\frac{84}{5}$

(iii) $8\div\frac{7}{3}=8\times\frac{1}{\frac{7}{3}}$

$=8\times\frac{3}{7}$

$=\frac{8\times3}{7}$

$=\frac{24}{7}$

(iv) $4\div\frac{8}{3}=4\times\frac{1}{\frac{8}{3}}$

$=4\times\frac{3}{8}$

$=\frac{4\times3}{8}$

$=\frac{3}{2}$

(v) $3\div2\frac{1}{3}=3\div\frac{2\times3+1}{3}$

$=3\div\frac{6+1}{3}$

$=3\div\frac{7}{3}$

$=3\times\frac{1}{\frac{7}{3}}$

$=3\times\frac{3}{7}$

$=\frac{3\times3}{7}$

$=\frac{9}{7}$

(vi) $5\div3\frac{4}{7}=5\div\frac{3\times7+4}{7}$

$=5\div\frac{21+4}{7}$

$=5\div\frac{25}{7}$

$=5\times\frac{1}{\frac{25}{7}}$

$=5\times\frac{7}{25}$

$=\frac{5\times7}{25}$

$=\frac{7}{5}$

raja
Updated on 10-Oct-2022 13:32:36

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