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Simplify:
1. $ 38-\{5-(-48) \div(-12) $
2. $ 30+\{-2 \times(25-23-10)\} $
Given:
1. $38-\{5-( -48) \div ( -12)\}$
2. $30+[\{-2\times ( 25-\overline{23-10})\}]$
To do:
We have to simplify the given expressions.
Solution:
We have to use Bodmas method in these type of problems.
1.
$ \begin{array}{l}
38-\{5-( -48) \div ( -12)\} =38-\left\{5-\left(\frac{-48}{-12}\right)\right\}\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =38-\{5-( 4)\}\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =38-\{5-4\}\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =38-1\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =37
\end{array}$.
2.
$ \begin{array}{l}
30+[\{-2\times ( 25-\overline{23-10})\}] =30+\{-2\times ( 25-13)\} \ \ \ \ \ \ \ [ Solving\ bar]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30+\{-2\times 12\}\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30+( -24)\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =30-24\ \ \ \ \ \ \ \ \ \ [( +) \times ( -) =( -)]\\
\\
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =6
\end{array}$.