Find:
$(i).\ 4.8 \div 10$
$(ii).\ 52.5 \div 10$
$(iii).\ 0.7 \div 10$
$(iv).\ 33.1 \div 10$
$(v).\ 272.23 \div 10$
(vi).\ 0.56 \div 10$
$(vii).\ 3.97 \div10$

AcademicMathematicsNCERTClass 7

To do:

We have to find

(i) $4.8 \div 10$

(ii) $52.5 \div 10$

(iii) $0.7 \div 10$

(iv) $33.1 \div 10$

(v) $272.23 \div 10$

(vi) $0.56 \div 10$

(vii) $3.97 \div10$

Solution:

We know that,

On dividing a decimal by $10^n$, the decimal point shifts to the left by $n$ places.

$\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$

Therefore,

(i) $4.8\div10=\frac{48}{10}\times\frac{1}{10}$

$=\frac{48}{100}$

$=0.48$

(ii) $52.5\div10$

$=\frac{525}{10}\times\frac{1}{10}$

$=\frac{525}{100}$

$=5.25$

(iii) $0.7\div10=\frac{7}{10}\times\frac{1}{10}$

$=\frac{7}{100}$

$=0.07$

(iv) $33.1\div10=\frac{331}{10}\times\frac{1}{10}$

$=\frac{331}{100}$

$=3.31$

(v) $272.23\div10=\frac{27223}{100}\times\frac{1}{10}$

$=\frac{27223}{1000}$

$=27.223$

(vi) $0.56\div10=\frac{56}{100}\times\frac{1}{10}$

$=\frac{56}{1000}$

$=0.056$

(vii) $3.97\div10=\frac{397}{100}\times\frac{1}{10}$

$=\frac{397}{1000}$

$=0.397$

raja
Updated on 10-Oct-2022 13:32:37

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