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Program to print 2D shapes in C++
In this tutorial, we will be discussing a program to print out 2D shapes.
For this we will be provided with the various parameters required to make a shape such as radius, side length and side breadth, etc. And our task is to print a shape accordingly with no thickness.
Example
#include <bits/stdc++.h>
using namespace std;
void print_circle(int radius){
for (int i = 0; i <= 2 * radius; i++){
for (int j = 0; j <= 2 * radius; j++){
double distance = sqrt((double)(i - radius) * (i -
radius) + (j - radius) * (j - radius));
if (distance > radius - 0.5 &&
distance < radius + 0.5)
printf("*");
else
printf(" ");
}
printf("\n");
}
}
void print_rectangle(int l, int b){
int i, j;
for (i = 1; i <= l; i++){
for (j = 1; j <= b; j++)
if (i == 1 || i == l || j == 1 || j == b)
printf("*");
else
printf(" ");
printf("\n");
}
}
void print_triangle(int side){
int i, j;
for (i = 1; i <= side; i++){
for (j = i; j < side; j++)
printf(" ");
for (j = 1; j <= (2 * i - 1); j++){
if (i == side || j == 1 || j == (2 * i - 1))
printf("*");
else
printf(" ");
}
printf("\n");
}
}
void print_hexagon(int length){
int l, j, i, k;
for (i = 1, k = length, l = 2 * length - 1; i < length;
i++, k--, l++){
for (j = 0; j < 3 * length; j++)
if (j >= k && j <= l)
printf("*");
else
printf(" ");
printf("\n");
}
for (i = 0, k = 1, l = 3 * length - 2; i < length; i++,
k++, l--){
for (j = 0; j < 3 * length; j++)
if (j >= k && j <= l)
printf("*");
else
printf(" ");
printf("\n");
}
}
void calc_pattern(int choice){
int radius, length, breadth, side;
switch (choice){
case 1:
radius = 4;
print_circle(radius);
break;
case 2:
length = 3, breadth = 8;
print_rectangle(length, breadth);
break;
case 3:
side = 6;
print_triangle(side);
break;
case 4:
side = 4;
print_hexagon(side);
break;
default:
printf("Invalid choice\n");
}
}
int main(){
int choice = 1;
calc_pattern(choice);
return 0;
}Output
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Updated on: 19-Dec-2019
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