Write True ( T ) or False ( F ) against each of the following statements :
(a) 16 : 24 :: 20 : 30
(b) 21: 6 :: 35 : 10
(c) 12 : 18 :: 28 : 12
(d) 8 : 9 :: 24 : 27
(e) 5.2 : 3.9 :: 3 : 4
(f) 0.9 : 0.36 :: 10 : 4.
To do:
We have to write True ( T ) or False ( F ) against each of the given statements.
Solution:
We know that,
The proportion is defined as the equality of two ratios.
If $p:q::r:s$ then,
$\frac{p}{q} = \frac{r}{s}$.
(a) 16:24:: 20:30
$16:24 = \frac{16}{24}$
$=\frac{2}{3}$
$20:30 = \frac{20}{30}$
$=\frac{2}{3}$
Since,
$16:24 = 20:30$
The given statement is True.
(b) 21: 6:: 35: 10
$21:6 = \frac{21}{6}$
$=\frac{7}{2}$
$35:10 = \frac{35}{10}$
$=\frac{7}{2}$
Since,
$21:6 = 35:10$
The given statement is True.
(c) 12 : 18 :: 28 : 12
$12:18 = \frac{12}{18}$
$=\frac{2}{3}$
$28:12 = \frac{28}{12}$
$=\frac{7}{3}$
Since,
$12:18 ≠ 28:12$
The given statement is False.
(d) 8 : 9:: 24: 27
$8 : 9 = \frac{8}{9}$
$24 : 27 = \frac{24}{27}$
$=\frac{8}{9}$
Since,
$8 : 9= 24 : 27$
The given statement is True.
(e) 5.2: 3.9:: 3: 4
$5.2 : 3.9 = \frac{5.2}{3.9}$
$=\frac{52}{39}$
$=\frac{4}{3}$
$3 : 4 =\frac{3}{4}
Since,
$5.2: 3.9 ≠ 3:4$
The given statement is False.
(f) 0.9 : 0.36 :: 10 : 4
$0.9 : 0.36 =\frac{0.9}{0.36}$
$=\frac{90}{36}$
$=\frac{10}{4}$
$10 : 4 = \frac{10}{4}$
Since,
$0.9 : 0.36 = 10 :4$
The given statement is True.
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