Simplify and solve the following linear equations.
$ 0.25(4 f-3)=0.05(10 f-9) $

AcademicMathematicsNCERTClass 8

Given:

$0.25(4 f-3)=0.05(10 f-9)$.

To do:

We have to solve the given linear equation.

Solution:

$0.25(4 f-3)=0.05(10 f-9)$

This implies,

$0.25(4 f)-0.25(3)=0.05(10 f)-0.05(9)$

$f-0.75=0.5f-0.45$

$f-0.5f=0.75-0.45$

$0.5f=0.30$

$f =\frac{0.3}{0.5}$

$f = \frac{3}{5}$

$f=0.6$

The value of $f$ is $0.6$.

raja
Updated on 10-Oct-2022 13:47:38

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