Solve: $ 0.25(4 f-3)=0.05(10 f-9) $

Given:

\( 0.25(4 f-3)=0.05(10 f-9) \)

To do:

We have to find the value of $f$.
Solution:

$0.25(4 f-3)=0.05(10 f-9)$

$0.25\times4f-0.25\times3=0.05\times10f-0.05\times9$

$f-0.75=0.5f-0.45$

$f-0.5f=0.75-0.45$

$0.5f=0.30$

$f=\frac{0.3}{0.5}$

$f=\frac{3}{5}$

The value of $f$ is $\frac{3}{5}$.

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Updated on: 10-Oct-2022

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