Fill in the blanks.
(a) $ (-8)+ $ ___ $ =0 $(b) $13 +$ _____ $= 0$
(c) $12 + (– 12) =$ ____
(d) $(– 4) +$ ____ $= – 12$
(e) ____ $– 15 = – 10$

AcademicMathematicsNCERTClass 6

To do :

We have to fill in the blanks.

Solution :

We know that,

$(+) \times (-) = (-)$

$(+) \times (+) = (+)$

$(-) \times (-) = (+)$

$(-) \times (+) = (-)$

(a) Let the number in the blank be $x$

This implies,

$(-8)+x=0$

Adding $+8$ on both sides, we get,

$(-8)+x+8=0+8$

$x+8-8=8$

$x=8$

Therefore,

$(-8)+ 8=0$

(b) Let the number in the blank be $x$

This implies,

$13+x=0$

Adding $-13$ on both sides, we get,

$13+x+(-13)=0+(-13)$

$x+13-13=-13$

$x=-13$

Therefore,

$13+ (-13)=0$

(c) Let the number in the blank be $x$

This implies,

$12+(-12)=x$

$12-12=x$

$x=0$

Therefore,

$12+ (-12)=0$

(d) Let the number in the blank be $x$

This implies,

$(-4)+x=(-12)$

Adding $+4$ on both sides, we get,

$(-4)+x+(+4)=(-12)+(+4)$

$x-4+4=-12+4$

$x=-(12-4)$

$x=-8$

Therefore,

$(-4)+ (-8)=(-12)$

(e) Let the number in the blank be $x$

This implies,

$x-15=-10$

Adding $+15$ on both sides, we get,

$x-15+(+15)=-10+(+15)$

$x-15+15=-10+15$

$x+15-15=15-10$

$x=5$

Therefore,

$5-15=-10$

raja
Updated on 10-Oct-2022 13:32:36

Advertisements