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Fill in the blanks.
(a) $ (-8)+ $ ___ $ =0 $(b) $13 +$ _____ $= 0$
(c) $12 + (– 12) =$ ____
(d) $(– 4) +$ ____ $= – 12$
(e) ____ $– 15 = – 10$
To do :
We have to fill in the blanks.
Solution :
We know that,
$(+) \times (-) = (-)$
$(+) \times (+) = (+)$
$(-) \times (-) = (+)$
$(-) \times (+) = (-)$
(a) Let the number in the blank be $x$
This implies,
$(-8)+x=0$
Adding $+8$ on both sides, we get,
$(-8)+x+8=0+8$
$x+8-8=8$
$x=8$
Therefore,
$(-8)+ 8=0$
(b) Let the number in the blank be $x$
This implies,
$13+x=0$
Adding $-13$ on both sides, we get,
$13+x+(-13)=0+(-13)$
$x+13-13=-13$
$x=-13$
Therefore,
$13+ (-13)=0$
(c) Let the number in the blank be $x$
This implies,
$12+(-12)=x$
$12-12=x$
$x=0$
Therefore,
$12+ (-12)=0$
(d) Let the number in the blank be $x$
This implies,
$(-4)+x=(-12)$
Adding $+4$ on both sides, we get,
$(-4)+x+(+4)=(-12)+(+4)$
$x-4+4=-12+4$
$x=-(12-4)$
$x=-8$
Therefore,
$(-4)+ (-8)=(-12)$
(e) Let the number in the blank be $x$
This implies,
$x-15=-10$
Adding $+15$ on both sides, we get,
$x-15+(+15)=-10+(+15)$
$x-15+15=-10+15$
$x+15-15=15-10$
$x=5$
Therefore,
$5-15=-10$