Find
(a) $ 35-(20) $
(b) $72 – (90)$
(c) $(– 15) – (– 18)$
(d) $(–20) – (13)$
(e) $23 – (– 12)$
(f) $(–32) – (– 40)$

To do :

We have to find the given sums.

Solution :

We know that,

$(+) \times (-) = (-)$

$(+) \times (+) = (+)$

$(-) \times (-) = (+)$

$(-) \times (+) = (-)$

(a) $35-(20)=35-20$

$=15$

Therefore,

\( 35-(20)=15 \)

(b) $72-(90)=72-90$

$=-(90-72)$

$=-18$

Therefore,

\( 72-(90)=-18 \)

(c) $(-15)-(-18)=-15+18$

$=18-15$

$=3$

Therefore,

\( (-15)-(-18)=3 \)

(d) $(-20)-(13)=-20-13$

$=-(20+13)$

$=-33$

Therefore,

\( (-20)-(13)=-33 \)

(e) $23-(-12)=23+12$

$=35$

Therefore,

\( 23-(-12)=35 \)

(f) $(-32)-(-40)=-32+40$

$=40-32$

$=8$

Therefore,

\( (-32)-(-40)=8 \)

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Updated on: 10-Oct-2022

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