What are the roots of $x^2-16 =0$?

Given: Equation $x^2-16 =0$.

To do: To find the root of $x^2-16 =0$.

Solution:

$x^2-16 =0$

$\Rightarrow x^2-4^2$

$\Rightarrow ( x-4)( x+4)=0$

If $x-4=0\Rightarrow x=4$

If $x+4=0\Rightarrow x=-4$

Thus, $x=-4,\ 4$.

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Updated on: 10-Oct-2022

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