Find the roots of the equation $x^{2}-3x-m( m+3)=0$.
Given: Equation $x^{2}-3x-m( m+3)=0$.
To do: To find the roots of the given equation.
Solution:
Given equation is: $x^{2}-3x-m( m+3)=0$.
$\Rightarrow x^{2}-3x-m^{2}-3m=0$
$\Rightarrow x^{2}-m^{2}-3x-3m=0$
$\Rightarrow ( x-m)( x+m)-3( x+m)=0$
$\Rightarrow ( x+m)( x-m-3)=0$
If $x+m=0$
$\Rightarrow x=-m$
If $x-m-3=0$
$\Rightarrow x=m+3$
$\therefore x=m,\ m+3$.
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