Two ores X and Y were taken. On heating these ores it was observed that(a) ore X gives CO₂ gas, and (b) ore Y gives SO₂ gas. Write steps to convert these ores into metals, giving chemical equations of the reactions that take place.

Academic Chemistry NCERT Class 10

(a) ore X gives CO2 gas, hence, it is a metal carbonate.

Calcination-

Metal carbonate heated strongly in the presence of limited supply of air it gives us:- $MCO_3 \xrightarrow {heat} MO + CO_2$

Reduction: The oxide ore is reduced with carbon (coke).

$MO + C \rightarrow M +CO$

(b) ore Y gives SO2 gas, hence, it is a metal sulphide.

Roasting- Metal sulphide heated in the presence of excess air, then it gives us:-

$MSO_3\xrightarrow {heat} [air] MO + SO_2$

Reduction: The metal oxide is reduced to metal by a most common reducing agent called carbon or coke.

$MO + C \rightarrow M +CO$

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Updated on: 10-Oct-2022

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