Two different dice are tossed together. Find the probability :
$( i)$ of getting a doublet
$( ii)$ of getting a sum 10, of the numbers on the two dice.

Given: Two different dice are tossed together.

To do: To find the probability :

$( i)$ Of getting a doublet.

$( ii)$ Of getting a sum 10, of the numbers on the two dice.

Solution:
$( i)$. Favorable outcomes of getting a doublet$= {(1, 1), (2, 2), (3, 3),(4, 4), (5, 5), (6, 6)}$

No. of favorable outcomes$=6$

Total possible outcomes$=6×6=36$

Probability of getting a doublet$=\frac{No.\ of\ favorable\ outcomes}{Total\
number\ of\ possible\ outcomes}$

                                                  $=\frac{6}{36}$

                                                  $=6$
$( ii)$. Events  getting sum of numbers as 10={(4, 6),(6, 4),(5, 5)}

Numbers of favorable outcomes$=3$

Total no. of possible outcomes$=36$

probability of  getting sum of numbers as 10$=\frac{3}{36}$

                                            $=\frac{1}{12}$
 

Updated on: 10-Oct-2022

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