Two dice are thrown simultaneously. The probability of getting a sum of $9$.

Given: Two dice are thrown simultaneously. 

To do: To find the probability of getting a sum of $9$.

When two dice were thrown

Total possible outcomes$=36$

Outcomes with total as 9 are: $[( 3,\ 6),\ ( 4,\ 5),\ ( 5,\ 4),\ ( 6,\ 3)]$

Required probability$=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

$=\frac{4}{36}$

$=\frac{1}{9}$

Thus, the probability of getting a sum of $9$ is $\frac{1}{9}$ when two dice are thrown.