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The paint in a certain container is sufficient to paint on area equal to $9.375\ m^2$. How many bricks of dimension $22.5\ cm \times 10\ cm \times 7.5\ cm$ can be painted out of this container?
Given:
The paint in a certain container is sufficient to paint an area equal to $9.375\ m^2$.
The dimensions of each brick is $22.5\ cm \times 10\ cm \times 7.5\ cm$.
To do:
We have to find the number of bricks that can be painted out of the container.
Solution:
Area of the place for painting $= 9.375\ m^2$
Dimension of each brick $= 22.5\ cm \times 10\ cm \times 7.5\ cm$
Therefore,
Surface area of each brick $= 2 (lb + bh + lh)$
$= 2(22.5 \times 10 + 10 \times 7.5 + 7.5 \times 22.5)$
$= 2(225 + 75 + 168.75)$
$= 2 \times 468.75$
$= 937.5\ cm^2$
This implies,
Number of bricks that can be painted $=\frac{\text { Total area }}{\text { Area of one brick }}$
$=\frac{9.375 \times 100 \times 100}{937.5}$
$=\frac{937.5 \times 100}{937.5}$
$=100$ bricks
Therefore, the number of bricks that can be painted out of the container is $100$ bricks.