A wall of length $10\ m$ was to be built across an open ground. The height of the wall is $4\ m$ and thickness of the wall is $24\ cm$. If this wall is to be built up with bricks whose dimensions are $24\ cm \times 12\ cm \times 8\ cm$, how many bricks would be required?

Given:

A wall of length $10\ m$ was to be built across an open ground.

The height of the wall is $4\ m$ and thickness of the wall is $24\ cm$. 

The wall is to be built up with bricks whose dimensions are $24\ cm \times 12\ cm \times 8\ cm$.

To do:

We have to find the number of bricks required.

Solution:

Length of the wall $(l) = 10\ m$

$= 10\times100$

$=1000\ cm$

Height of the wall $(h) = 4\ m$

$= 400\ cm$

Thickness of the wall $(b) = 24\ cm$

Therefore,

Volume of the wall $= lbh$

$= 1000 \times 24 \times 400$

$= 9600000\ cm^3$

Dimensions of each brick $= 24\ cm \times 12\ cm \times 8\ cm$

$= 2304\ cm^3$

Number of bricks required $=\frac{\text { Volume of wall }}{\text { Volume of one brick }}$

$=\frac{9600000}{2304}$

$=4167$ bricks

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Updated on: 10-Oct-2022

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