- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# A cistern, internally measuring $ 150 \mathrm{~cm} \times 120 \mathrm{~cm} \times 110 \mathrm{~cm} $, has $ 129600 \mathrm{~cm}^{3} $ of water in it. Porous bricks are placed in the water until the cistern is full to the brim. Each brick absorbs one-seventeenth of its own volume of water. How many bricks can be put in without overflowing the water, each brick being $ 22.5 \mathrm{~cm} \times 7.5 \mathrm{~cm} \times 6.5 \mathrm{~cm} $ ?

Given:

A cistern, internally measuring \( 150 \mathrm{~cm} \times 120 \mathrm{~cm} \times 110 \mathrm{~cm} \), has \( 129600 \mathrm{~cm}^{3} \) of water in it.

Porous bricks are placed in the water until the cistern is full to the brim.

Each brick absorbs one-seventeenth of its own volume of water.

Dimensions of each is \( 22.5 \mathrm{~cm} \times 7.5 \mathrm{~cm} \times 6.5 \mathrm{~cm} \).

To do:

We have to find the number of bricks that can be put in without overflowing the water.

Solution:

The dimensions of the cistern are \( 150 \mathrm{~cm} \times 120 \mathrm{~cm} \times 110 \mathrm{~cm} \)

This implies,

Volume of the cistern $= 1980000\ cm^3$

Volume of water in the cistern $=129600 \mathrm{~cm}^{3}$

Volume of the bricks to be filled in cistern $= 1980000 - 129600\ cm^3$

$=1850400\ cm^3$

Dimensions of each is \( 22.5 \mathrm{~cm} \times 7.5 \mathrm{~cm} \times 6.5 \mathrm{~cm} \).

Let the number of bricks placed be $n$.

Therefore,

Volume of $n$ bricks $= n \times 22.5 \times 7.5 \times 6.5$

Each brick absorbs one-seventeenth of its own volume.

The volume of water absorbed by $n$ bricks $=\frac{n}{17} \times 22.5 \times 7.5 \times 6.5$

Therefore,

The volume of $n$ bricks $=$ Volume of water absorbed by $n$ bricks $+$ Volume to be filled in cistern

$n \times 22.5 \times 7.5 \times 6.5=1850400+\frac{n}{17} \times 22.5 \times 7.5 \times 6.5$

$\frac{17n-n}{17} \times 22.5 \times 7.5 \times 6.5=1850400$

$\frac{16n}{17} \times 22.5 \times 7.5 \times 6.5=1850400$

$n = 1792.41$

Hence, the number of bricks which can be put in the cistern without overflowing the water is $1792$.

- Related Questions & Answers
- Call if minus (CM) in 8085 Microprocessor
- Converting km per hour to cm per second using JavaScript
- How to apply a 3×3 convolution matrix using imageconvolution() in PHP?
- Number of Ways to Paint N × 3 Grid in C++
- Number of Ways to Paint N × 3 Grid in C++ program
- How to execute a particular test method multiple times (say 5 times) in TestNG?
- Number of times a string appears in another JavaScript
- Filling diagonal to make the sum of every row, column and diagonal equal of 3×3 matrix using c++
- Print the string after the specified character has occurred given no. of times in C Program
- Is it possible to utilize $addToSet multiple times in the same update?
- How are the times a user presses the button counted in jQuery?
- Concatenate a string given number of times in C++ programming
- Checking for overlapping times JavaScript
- How to create a data frame in R with repeated rows by a sequence of number of times or by a fixed number of times?
- Deleting occurrences of an element if it occurs more than n times using JavaScript
- Repeating tuples N times in Python